It seems that $ 11x^{2}+5x+36 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 11 }$ by the constant term $\color{blue}{c = 36} $.
$$ a \cdot c = 396 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 396 $ and add to $ b = 5 $.
Step 4: All pairs of numbers with a product of $ 396 $ are:
PRODUCT = 396 | |
1 396 | -1 -396 |
2 198 | -2 -198 |
3 132 | -3 -132 |
4 99 | -4 -99 |
6 66 | -6 -66 |
9 44 | -9 -44 |
11 36 | -11 -36 |
12 33 | -12 -33 |
18 22 | -18 -22 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 5 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 5 }$, we conclude the polynomial cannot be factored.