It seems that $ 10x^{2}+13x+11 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 10 }$ by the constant term $\color{blue}{c = 11} $.
$$ a \cdot c = 110 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 110 $ and add to $ b = 13 $.
Step 4: All pairs of numbers with a product of $ 110 $ are:
PRODUCT = 110 | |
1 110 | -1 -110 |
2 55 | -2 -55 |
5 22 | -5 -22 |
10 11 | -10 -11 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 13 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 13 }$, we conclude the polynomial cannot be factored.