Factor polynomial $$ 50y^{5}-36y^{4}+100y^{3}-120y^{2}-12y $$
Answer
$$ 50y^{5}-36y^{4}+100y^{3}-120y^{2}-12y = 2y( 25y^{4}-18y^{3}+50y^{2}-60y-6 ) $$
Explanation
After factoring out $ 2y $ we have:
$$ 50y^{5}-36y^{4}+100y^{3}-120y^{2}-12y = 2y ( 25y^{4}-18y^{3}+50y^{2}-60y-6 ) $$This page was created using
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