Factor polynomial $$ 100y^{2}-49x^{4} $$
Answer
$$ 100y^{2}-49x^{4} = (10y+7x^{2})(10y-7x^{2}) $$
Explanation
Rewrite $ 100y^2-49x^4 $ as:
$$ \color{blue}{ 100y^2-49x^4 = (10y)^2 - (7x^2)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 10y $ and $ II = 7x^2 $ , we have:
$$ 100y^2-49x^4 = (10y)^2 - (7x^2)^2 = ( 10y-7x^2 ) ( 10y+7x^2 ) $$This page was created using
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