Factor polynomial $$ 100x^{2}-121y^{2} $$
Answer
$$ 100x^{2}-121y^{2} = (10x+11y)(10x-11y) $$
Explanation
Rewrite $ 100x^2-121y^2 $ as:
$$ \color{blue}{ 100x^2-121y^2 = (10x)^2 - (11y)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 10x $ and $ II = 11y $ , we have:
$$ 100x^2-121y^2 = (10x)^2 - (11y)^2 = ( 10x-11y ) ( 10x+11y ) $$This page was created using
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