Factor polynomial $$ 1-9a^{6}b^{4} $$
Answer
$$ 1-9a^{6}b^{4} = (1+3a^{3}b^{2})(1-3a^{3}b^{2}) $$
Explanation
Rewrite $ 1-9a^6b^4 $ as:
$$ \color{blue}{ 1-9a^6b^4 = (1)^2 - (3a^3b^2)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 1 $ and $ II = 3a^3b^2 $ , we have:
$$ 1-9a^6b^4 = (1)^2 - (3a^3b^2)^2 = ( 1-3a^3b^2 ) ( 1+3a^3b^2 ) $$This page was created using
Polynomial Factoring Calculator