Rewrite $ 1-121x^4y^4 $ as:
$$ \color{blue}{ 1-121x^4y^4 = (1)^2 - (11x^2y^2)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 1 $ and $ II = 11x^2y^2 $ , we have:
$$ 1-121x^4y^4 = (1)^2 - (11x^2y^2)^2 = ( 1-11x^2y^2 ) ( 1+11x^2y^2 ) $$