Step 1 :
After factoring out $ -1 $ we have:
$$ -x^{2}-2x+3 = - ~ ( x^{2}+2x-3 ) $$Step 2 :
Step 2: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 2 } ~ \text{ and } ~ \color{red}{ c = -3 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 2 } $ and multiply to $ \color{red}{ -3 } $.
Step 3: Find out pairs of numbers with a product of $\color{red}{ c = -3 }$.
PRODUCT = -3 | |
-1 3 | 1 -3 |
Step 4: Find out which pair sums up to $\color{blue}{ b = 2 }$
PRODUCT = -3 and SUM = 2 | |
-1 3 | 1 -3 |
Step 5: Put -1 and 3 into placeholders to get factored form.
$$ \begin{aligned} x^{2}+2x-3 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ x^{2}+2x-3 & = (x -1)(x + 3) \end{aligned} $$