Factor polynomial $$ -9x^{5}+49x^{3} $$
Answer
$$ -9x^{5}+49x^{3} = x^{3}( -3x+7 )( 3x+7 ) $$
Explanation
Step 1 :
After factoring out $ x^{3} $ we have:
$$ -9x^{5}+49x^{3} = x^{3} ( -9x^{2}+49 ) $$Step 2 :
Rewrite $ -9x^{2}+49 $ as:
$$ -9x^{2}+49 = 49 -9x^2 = (7)^2 - (3x)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 7 $ and $ II = 3x $ , we have:
$$ -9x^{2}+49 = (7)^2 - (3x)^2 = ( -3x+7 ) ( 3x+7 ) $$This page was created using
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