It seems that $ -14x^{2}+10x+9 $ cannot be factored out.
Step 1 :
After factoring out $ -1 $ we have:
$$ -14x^{2}+10x+9 = - ~ ( 14x^{2}-10x-9 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 14 }$ by the constant term $\color{blue}{c = -9} $.
$$ a \cdot c = -126 $$Step 4: Find out two numbers that multiply to $ a \cdot c = -126 $ and add to $ b = -10 $.
Step 5: All pairs of numbers with a product of $ -126 $ are:
PRODUCT = -126 | |
-1 126 | 1 -126 |
-2 63 | 2 -63 |
-3 42 | 3 -42 |
-6 21 | 6 -21 |
-7 18 | 7 -18 |
-9 14 | 9 -14 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = -10 }$
Step 7: Because none of these pairs will give us a sum of $ \color{blue}{ -10 }$, we conclude the polynomial cannot be factored.