It seems that $ -5x^{2}-8x+6 $ cannot be factored out.
Step 1 :
After factoring out $ -1 $ we have:
$$ -5x^{2}-8x+6 = - ~ ( 5x^{2}+8x-6 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 5 }$ by the constant term $\color{blue}{c = -6} $.
$$ a \cdot c = -30 $$Step 4: Find out two numbers that multiply to $ a \cdot c = -30 $ and add to $ b = 8 $.
Step 5: All pairs of numbers with a product of $ -30 $ are:
PRODUCT = -30 | |
-1 30 | 1 -30 |
-2 15 | 2 -15 |
-3 10 | 3 -10 |
-5 6 | 5 -6 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = 8 }$
Step 7: Because none of these pairs will give us a sum of $ \color{blue}{ 8 }$, we conclude the polynomial cannot be factored.