Step 1 :
After factoring out $ -x $ we have:
$$ -4x^{3}-3x^{2}+x = -x ( 4x^{2}+3x-1 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 4 }$ by the constant term $\color{blue}{c = -1} $.
$$ a \cdot c = -4 $$Step 4: Find out two numbers that multiply to $ a \cdot c = -4 $ and add to $ b = 3 $.
Step 5: All pairs of numbers with a product of $ -4 $ are:
PRODUCT = -4 | |
-1 4 | 1 -4 |
-2 2 | 2 -2 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = 3 }$
PRODUCT = -4 and SUM = 3 | |
-1 4 | 1 -4 |
-2 2 | 2 -2 |
Step 7: Replace middle term $ 3 x $ with $ 4x-x $:
$$ 4x^{2}+3x-1 = 4x^{2}+4x-x-1 $$Step 8: Apply factoring by grouping. Factor $ 4x $ out of the first two terms and $ -1 $ out of the last two terms.
$$ 4x^{2}+4x-x-1 = 4x\left(x+1\right) -1\left(x+1\right) = \left(4x-1\right) \left(x+1\right) $$