It seems that $ -8x^{2}-12x-3 $ cannot be factored out.
Step 1 :
After factoring out $ -1 $ we have:
$$ -8x^{2}-12x-3 = - ~ ( 8x^{2}+12x+3 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 8 }$ by the constant term $\color{blue}{c = 3} $.
$$ a \cdot c = 24 $$Step 4: Find out two numbers that multiply to $ a \cdot c = 24 $ and add to $ b = 12 $.
Step 5: All pairs of numbers with a product of $ 24 $ are:
PRODUCT = 24 | |
1 24 | -1 -24 |
2 12 | -2 -12 |
3 8 | -3 -8 |
4 6 | -4 -6 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = 12 }$
Step 7: Because none of these pairs will give us a sum of $ \color{blue}{ 12 }$, we conclude the polynomial cannot be factored.