Step 1 :
After factoring out $ -2a^{4} $ we have:
$$ -4a^{6}+8a^{5}-2a^{4} = -2a^{4} ( 2a^{2}-4a+1 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 2 }$ by the constant term $\color{blue}{c = 1} $.
$$ a \cdot c = 2 $$Step 4: Find out two numbers that multiply to $ a \cdot c = 2 $ and add to $ b = -4 $.
Step 5: All pairs of numbers with a product of $ 2 $ are:
PRODUCT = 2 | |
1 2 | -1 -2 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = -4 }$
Step 7: Because none of these pairs will give us a sum of $ \color{blue}{ -4 }$, we conclude the polynomial cannot be factored.