Step 1 :
After factoring out $ -1 $ we have:
$$ -2x^{2}+7x+4 = - ~ ( 2x^{2}-7x-4 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 2 }$ by the constant term $\color{blue}{c = -4} $.
$$ a \cdot c = -8 $$Step 4: Find out two numbers that multiply to $ a \cdot c = -8 $ and add to $ b = -7 $.
Step 5: All pairs of numbers with a product of $ -8 $ are:
PRODUCT = -8 | |
-1 8 | 1 -8 |
-2 4 | 2 -4 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = -7 }$
PRODUCT = -8 and SUM = -7 | |
-1 8 | 1 -8 |
-2 4 | 2 -4 |
Step 7: Replace middle term $ -7 x $ with $ x-8x $:
$$ 2x^{2}-7x-4 = 2x^{2}+x-8x-4 $$Step 8: Apply factoring by grouping. Factor $ x $ out of the first two terms and $ -4 $ out of the last two terms.
$$ 2x^{2}+x-8x-4 = x\left(2x+1\right) -4\left(2x+1\right) = \left(x-4\right) \left(2x+1\right) $$