It seems that $ 13x^{2}-27x+10 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 13 }$ by the constant term $\color{blue}{c = 10} $.
$$ a \cdot c = 130 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 130 $ and add to $ b = -27 $.
Step 4: All pairs of numbers with a product of $ 130 $ are:
PRODUCT = 130 | |
1 130 | -1 -130 |
2 65 | -2 -65 |
5 26 | -5 -26 |
10 13 | -10 -13 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = -27 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ -27 }$, we conclude the polynomial cannot be factored.