Factor polynomial $$ -20xy+4y^{2}+25x^{2} $$
Answer
$$ -20xy+4y^{2}+25x^{2} = (2y-5x)(2y-5x) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ -1 } $:
$$ -20xy+4y^2+25x^2 = -1 ( 20xy-4y^2-25x^2 ) $$Step 2 :
Note that the polynomial $ -20xy+4y^2+25x^2 $ is a perfect square trinomial, so we will use the following formula.
$$ A^2 - 2AB + B^2 = (A - B)^2 $$In this example we have $ \color{blue}{ A = 2y } $ and $ \color{red}{ B = 5x } $ so,
$$ -20xy+4y^2+25x^2 = ( \color{blue}{ 2y } - \color{red}{ 5x } )^2 $$This page was created using
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