$$z^3+48z^2 = 0$$
Answer
$$ \begin{matrix}z_1 = 0 & z_2 = -48 \\[1 em] \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ x^{3}+48x^{2} = 0 } $, first we need to factor our $ x^2 $.
$$ x^{3}+48x^{2} = x^2 \left( x+48 \right) $$$ x = 0 $ is a root of multiplicity $ 2 $.
The second root can be found by solving equation $ x+48 = 0$.
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