$$x\cdot4-8x\cdot2+16 = 0$$
Answer
$$ x = \frac{4}{3} $$
Explanation
$$ \begin{aligned} x\cdot4-8x\cdot2+16 &= 0&& \text{simplify left side} \\[1 em]4x-16x+16 &= 0&& \\[1 em]-12x+16 &= 0&& \text{ move the constants to the right } \\[1 em]-12x &= -16&& \text{ divide both sides by $ -12 $ } \\[1 em]x &= \frac{-16}{-12}&& \\[1 em]x &= \frac{4}{3}&& \\[1 em] \end{aligned} $$
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