$$x\cdot3-3x\cdot2-3x-5 = 0$$
Answer
$$ x = -\frac{5}{6} $$
Explanation
$$ \begin{aligned} x\cdot3-3x\cdot2-3x-5 &= 0&& \text{simplify left side} \\[1 em]x\cdot3-3x\cdot2-3x-5 &= 0&& \\[1 em]3x-6x-3x-5 &= 0&& \\[1 em]3x-6x-3x-5 &= 0&& \\[1 em]-6x-5 &= 0&& \text{ move the constants to the right } \\[1 em]-6x &= 5&& \text{ divide both sides by $ -6 $ } \\[1 em]x &= -\frac{5}{6}&& \\[1 em] \end{aligned} $$
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