$$x-7 \cdot \frac{x^1}{2}+10 = 0$$

$$ \begin{aligned} x-7 \cdot \frac{x^1}{2}+10 &= 0&& \text{multiply ALL terms by } \color{blue}{ 2 }. \\[1 em]2x-2\cdot7 \cdot \frac{x^1}{2}+2\cdot10 &= 2\cdot0&& \text{cancel out the denominators} \\[1 em]2x-7x+20 &= 0&& \text{simplify left side} \\[1 em]-5x+20 &= 0&& \text{ move the constants to the right } \\[1 em]-5x &= -20&& \text{ divide both sides by $ -5 $ } \\[1 em]x &= \frac{-20}{-5}&& \\[1 em]x &= 4&& \\[1 em] \end{aligned} $$

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