In order to solve $ \color{blue}{ x^{5}-2x^{4}-3x^{3} = 0 } $, first we need to factor our $ x^3 $.
$$ x^{5}-2x^{4}-3x^{3} = x^3 \left( x^{2}-2x-3 \right) $$$ x = 0 $ is a root of multiplicity $ 3 $.
The remaining roots can be found by solving equation $ x^{2}-2x-3 = 0$.
$ x^{2}-2x-3 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.