$$x^3-2x^2 = 63x$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -7 & x_3 = 9 \end{matrix} $$
Explanation
$$ \begin{aligned} x^3-2x^2 &= 63x&& \text{move all terms to the left hand side } \\[1 em]x^3-2x^2-63x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ x^{3}-2x^{2}-63x = 0 } $, first we need to factor our $ x $.
$$ x^{3}-2x^{2}-63x = x \left( x^{2}-2x-63 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ x^{2}-2x-63 = 0$.
$ x^{2}-2x-63 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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