$$x^2+x+0 = 3$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 13 }}{ 2 } & x_2 = -\dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 13 }}{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x^2+x+0 &= 3&& \text{move all terms to the left hand side } \\[1 em]x^2+x+0-3 &= 0&& \text{simplify left side} \\[1 em]x^2+x+0-3 &= 0&& \\[1 em]x^2+x-3 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+x-3 = 0 $ is a quadratic equation.
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