$$x^2-4x-8x+4 = 0$$
Answer
$$ \begin{matrix}x_1 = 6-4 \sqrt{ 2 } & x_2 = 6+4 \sqrt{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x^2-4x-8x+4 &= 0&& \text{simplify left side} \\[1 em]x^2-12x+4 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-12x+4 = 0 $ is a quadratic equation.
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