$$x^2-\frac{495}{100}x+\frac{45}{10} = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 6 }{ 5 } & x_2 = \dfrac{ 15 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x^2-\frac{495}{100}x+\frac{45}{10} &= 0&& \text{multiply ALL terms by } \color{blue}{ 100 }. \\[1 em]100x^2-100 \cdot \frac{495}{100}x+100\cdot\frac{45}{10} &= 100\cdot0&& \text{cancel out the denominators} \\[1 em]100x^2-495x+450 &= 0&& \\[1 em] \end{aligned} $$
$ 100x^{2}-495x+450 = 0 $ is a quadratic equation.
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