$$x^2-14x+49 = 7$$
Answer
$$ \begin{matrix}x_1 = 7-\sqrt{ 7 } & x_2 = 7+\sqrt{ 7 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x^2-14x+49 &= 7&& \text{move all terms to the left hand side } \\[1 em]x^2-14x+49-7 &= 0&& \text{simplify left side} \\[1 em]x^2-14x+42 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-14x+42 = 0 $ is a quadratic equation.
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