$$x^2-\frac{14}{10}x-\frac{48}{100} = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 7 }{ 10 }-\dfrac{\sqrt{ 97 }}{ 10 } & x_2 = \dfrac{ 7 }{ 10 }+\dfrac{\sqrt{ 97 }}{ 10 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x^2-\frac{14}{10}x-\frac{48}{100} &= 0&& \text{multiply ALL terms by } \color{blue}{ 100 }. \\[1 em]100x^2-100 \cdot \frac{14}{10}x-100\cdot\frac{48}{100} &= 100\cdot0&& \text{cancel out the denominators} \\[1 em]100x^2-140x-48 &= 0&& \\[1 em] \end{aligned} $$
$ 100x^{2}-140x-48 = 0 $ is a quadratic equation.
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