$$\frac{x^2}{x}-5 = 0$$

$$ \begin{aligned} \frac{x^2}{x}-5 &= 0&& \text{multiply ALL terms by } \color{blue}{ x }. \\[1 em]x \cdot \frac{x^2}{x}-x\cdot5 &= x\cdot0&& \text{cancel out the denominators} \\[1 em]1-5x &= 0&& \text{ move the constants to the right } \\[1 em]-5x &= -1&& \text{ divide both sides by $ -5 $ } \\[1 em]x &= \frac{-1}{-5}&& \\[1 em]x &= \frac{1}{5}&& \\[1 em] \end{aligned} $$

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