$$x^2(9x^4+7) = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 0.66405+0.66405i & x_3 = 0.66405-0.66405i \\[1 em] x_4 = -0.66405+0.66405i & x_5 = -0.66405-0.66405i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x^2(9x^4+7) &= 0&& \text{simplify left side} \\[1 em]9x^6+7x^2 &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 9x^{6}+7x^{2} = 0 } $, first we need to factor our $ x^2 $.
$$ 9x^{6}+7x^{2} = x^2 \left( 9x^{4}+7 \right) $$$ x = 0 $ is a root of multiplicity $ 2 $.
The remaining roots can be found by solving equation $ 9x^{4}+7 = 0$.
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
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