$$x(x-3)(x+5) = 24$$
Answer
$$ \begin{matrix}x_1 = -1.52644 & x_2 = 3.73549 & x_3 = -4.20905 \end{matrix} $$
Explanation
$$ \begin{aligned} x(x-3)(x+5) &= 24&& \text{simplify left side} \\[1 em](x^2-3x)(x+5) &= 24&& \\[1 em]x^3+5x^2-3x^2-15x &= 24&& \\[1 em]x^3+2x^2-15x &= 24&& \text{move all terms to the left hand side } \\[1 em]x^3+2x^2-15x-24 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
This page was created using
Polynomial Equations Solver