$$ \begin{aligned} x(2x-7) &= (2x+2)(x-6)&& \text{simplify left and right hand side} \\[1 em]2x^2-7x &= 2x^2-12x+2x-12&& \\[1 em]2x^2-7x &= 2x^2-10x-12&& \text{move all terms to the left hand side } \\[1 em]2x^2-7x-2x^2+10x+12 &= 0&& \text{simplify left side} \\[1 em]2x^2-7x-2x^2+10x+12 &= 0&& \\[1 em]3x+12 &= 0&& \text{ move the constants to the right } \\[1 em]3x &= -12&& \text{ divide both sides by $ 3 $ } \\[1 em]x &= -\frac{12}{3}&& \\[1 em]x &= -4&& \\[1 em] \end{aligned} $$
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