$$w^3+5w^2+28-w = 0$$
Answer
$$ \begin{matrix}w_1 = -5.95694 & w_2 = 0.47847+2.11459i & w_3 = 0.47847-2.11459i \end{matrix} $$
Explanation
$$ \begin{aligned} w^3+5w^2+28-w &= 0&& \text{simplify left side} \\[1 em]w^3+5w^2-w+28 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
This page was created using
Polynomial Equations Solver