$$p\cdot2-31p+108 = 0$$
Answer
$$ p = \frac{108}{29} $$
Explanation
$$ \begin{aligned} p\cdot2-31p+108 &= 0&& \text{simplify left side} \\[1 em]p\cdot2-31p+108 &= 0&& \\[1 em]-29p+108 &= 0&& \text{ move the constants to the right } \\[1 em]-29p &= -108&& \text{ divide both sides by $ -29 $ } \\[1 em]p &= \frac{-108}{-29}&& \\[1 em]p &= \frac{108}{29}&& \\[1 em] \end{aligned} $$
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