$$d^2+38 = -7$$
Answer
$$ \begin{matrix}d_1 = 3 \sqrt{ 5 } i & d_2 = -3 \sqrt{ 5 } i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} d^2+38 &= -7&& \text{move all terms to the left hand side } \\[1 em]d^2+38+7 &= 0&& \text{simplify left side} \\[1 em]d^2+45 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+45 = 0 $ is a quadratic equation.
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