$$9z^2-4^2z+49 = 0$$
Answer
$$ \begin{matrix}z_1 = \dfrac{ 8 }{ 9 }+\dfrac{\sqrt{ 377 }}{ 9 }i & z_2 = \dfrac{ 8 }{ 9 }-\dfrac{\sqrt{ 377 }}{ 9 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 9z^2-4^2z+49 &= 0&& \text{simplify left side} \\[1 em]9z^2-16z+49 &= 0&& \\[1 em] \end{aligned} $$
$ 9x^{2}-16x+49 = 0 $ is a quadratic equation.
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