$$9x^3-8x^2 = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 8 }{ 9 } \\[1 em] \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 9x^{3}-8x^{2} = 0 } $, first we need to factor our $ x^2 $.
$$ 9x^{3}-8x^{2} = x^2 \left( 9x-8 \right) $$$ x = 0 $ is a root of multiplicity $ 2 $.
The second root can be found by solving equation $ 9x-8 = 0$.
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