$9 x^{3} - 8 x^{2} = 0$

Answer

$x_{1} = 0 x_{2} = \frac{8}{9}$

Explanation

In order to solve $9 x^{3} - 8 x^{2} = 0$ , first we need to factor our $x^{2}$ .

9 x^{3} - 8 x^{2} = x^{2} (9 x - 8)

$x = 0$ is a root of multiplicity $2$ .

The second root can be found by solving equation $9 x - 8 = 0$ .

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9x3−8x2=0

x1​=0​x2​=98​​

$9 x^{3} - 8 x^{2} = 0$

$x_{1} = 0 x_{2} = \frac{8}{9}$