$$8(n^2-n+6) = 0$$
Answer
$$ \begin{matrix}n_1 = \dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 23 }}{ 2 }i & n_2 = \dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 23 }}{ 2 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 8(n^2-n+6) &= 0&& \text{simplify left side} \\[1 em]8n^2-8n+48 &= 0&& \\[1 em] \end{aligned} $$
$ 8x^{2}-8x+48 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver