$$7x^3+21x^2-63x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -\dfrac{ 3 }{ 2 }-\dfrac{ 3 \sqrt{ 5}}{ 2 } & x_3 = -\dfrac{ 3 }{ 2 }+\dfrac{ 3 \sqrt{ 5}}{ 2 } \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 7x^{3}+21x^{2}-63x = 0 } $, first we need to factor our $ x $.
$$ 7x^{3}+21x^{2}-63x = x \left( 7x^{2}+21x-63 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 7x^{2}+21x-63 = 0$.
$ 7x^{2}+21x-63 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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