$$7a-13a^2-3 = 0$$
Answer
$$ \begin{matrix}a_1 = \dfrac{ 7 }{ 26 }+\dfrac{\sqrt{ 107 }}{ 26 }i & a_2 = \dfrac{ 7 }{ 26 }-\dfrac{\sqrt{ 107 }}{ 26 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 7a-13a^2-3 &= 0&& \text{simplify left side} \\[1 em]-13a^2+7a-3 &= 0&& \\[1 em] \end{aligned} $$
$ -13x^{2}+7x-3 = 0 $ is a quadratic equation.
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