$$6x^3+7x^2-5x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 1 }{ 2 } & x_3 = -\dfrac{ 5 }{ 3 } \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 6x^{3}+7x^{2}-5x = 0 } $, first we need to factor our $ x $.
$$ 6x^{3}+7x^{2}-5x = x \left( 6x^{2}+7x-5 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 6x^{2}+7x-5 = 0$.
$ 6x^{2}+7x-5 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver