$$6 \cdot \frac{x^2}{x}+4\frac{x}{x} = 0$$

$$ \begin{aligned} 6 \cdot \frac{x^2}{x}+4\frac{x}{x} &= 0&& \text{multiply ALL terms by } \color{blue}{ x }. \\[1 em]x\cdot6 \cdot \frac{x^2}{x}+x\cdot4\frac{x}{x} &= x\cdot0&& \text{cancel out the denominators} \\[1 em]6+4x &= 0&& \text{ move the constants to the right } \\[1 em]4x &= -6&& \text{ divide both sides by $ 4 $ } \\[1 em]x &= -\frac{6}{4}&& \\[1 em]x &= -\frac{3}{2}&& \\[1 em] \end{aligned} $$

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