$$6\cdot(5+1)-4\cdot(1+1) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 6\cdot(5+1)-4\cdot(1+1) &= 0&& \text{simplify left side} \\[1 em]6\cdot6-4\cdot2 &= 0&& \\[1 em]36-8 &= 0&& \\[1 em]28 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 28 = 0 } $ is FALSE, we conclude that the equation has no solution.
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