$$5 \cdot \frac{x^1}{2}+4\frac{x^1}{4}-3x = 0$$

$$ \begin{aligned} 5 \cdot \frac{x^1}{2}+4\frac{x^1}{4}-3x &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4\cdot5 \cdot \frac{x^1}{2}+4\cdot4\frac{x^1}{4}-4\cdot3x &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]10x+4x-12x &= 0&& \text{simplify left side} \\[1 em]2x &= 0&& \text{ divide both sides by $ 2 $ } \\[1 em]x &= \frac{0}{2}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$

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