$$50d^2+13d = 0$$
Answer
$$ \begin{matrix}d_1 = 0 & d_2 = -\dfrac{ 13 }{ 50 } \\[1 em] \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 50x^{2}+13x = 0 } $, first we need to factor our $ x $.
$$ 50x^{2}+13x = x \left( 50x+13 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 50x+13 = 0$.
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