$$5(x-4)(2x-3) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 3 }{ 2 } & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 5(x-4)(2x-3) &= 0&& \text{simplify left side} \\[1 em](5x-20)(2x-3) &= 0&& \\[1 em]10x^2-15x-40x+60 &= 0&& \\[1 em]10x^2-55x+60 &= 0&& \\[1 em] \end{aligned} $$
$ 10x^{2}-55x+60 = 0 $ is a quadratic equation.
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