$$4x^2+41x+98 = 2-3x$$
Answer
$$ \begin{matrix}x_1 = -3 & x_2 = -8 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4x^2+41x+98 &= 2-3x&& \text{move all terms to the left hand side } \\[1 em]4x^2+41x+98-2+3x &= 0&& \text{simplify left side} \\[1 em]4x^2+44x+96 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+44x+96 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver