$$4x(3x+3)(x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 1 & x_3 = -1 \end{matrix} $$
Explanation
$$ \begin{aligned} 4x(3x+3)(x-1) &= 0&& \text{simplify left side} \\[1 em](12x^2+12x)(x-1) &= 0&& \\[1 em]12x^3-12x^2+12x^2-12x &= 0&& \\[1 em]12x^3-12x^2+12x^2-12x &= 0&& \\[1 em]12x^3-12x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 12x^{3}-12x = 0 } $, first we need to factor our $ x $.
$$ 12x^{3}-12x = x \left( 12x^{2}-12 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 12x^{2}-12 = 0$.
$ 12x^{2}-12 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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