$$4(x+2)^2+1 = 0$$
Answer
$$ \begin{matrix}x_1 = -2+\dfrac{ 1 }{ 2 }i & x_2 = -2-\dfrac{ 1 }{ 2 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4(x+2)^2+1 &= 0&& \text{simplify left side} \\[1 em]4(x^2+4x+4)+1 &= 0&& \\[1 em]4x^2+16x+16+1 &= 0&& \\[1 em]4x^2+16x+17 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+16x+17 = 0 $ is a quadratic equation.
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