$$3x-2(x+4) = 5(x+1)+3$$

$$ \begin{aligned} 3x-2(x+4) &= 5(x+1)+3&& \text{simplify left and right hand side} \\[1 em]3x-(2x+8) &= 5x+5+3&& \\[1 em]3x-2x-8 &= 5x+8&& \\[1 em]x-8 &= 5x+8&& \text{move the $ \color{blue}{ 5x } $ to the left side and $ \color{blue}{ -8 }$ to the right} \\[1 em]x-5x &= 8+8&& \text{simplify left and right hand side} \\[1 em]-4x &= 16&& \text{ divide both sides by $ -4 $ } \\[1 em]x &= -\frac{16}{4}&& \\[1 em]x &= -4&& \\[1 em] \end{aligned} $$

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